(4/r^2)+(3/r)=1

Solution for (4/r^2)+(3/r)=1 equation:

D( r )

r = 0

r^2 = 0

r = 0

r = 0

r^2 = 0

r^2 = 0

1*r^2 = 0 // : 1

r^2 = 0

r = 0

r in (-oo:0) U (0:+oo)

3/r+4/(r^2) = 1 // - 1

3/r+4/(r^2)-1 = 0

3*r^-1+4*r^-2-1 = 0

t_1 = r^-1

4*t_1^2+3*t_1^1-1 = 0

4*t_1^2+3*t_1-1 = 0

DELTA = 3^2-(-1*4*4)

DELTA = 25

DELTA > 0

t_1 = (25^(1/2)-3)/(2*4) or t_1 = (-25^(1/2)-3)/(2*4)

t_1 = 1/4 or t_1 = -1

t_1 = -1

r^-1+1 = 0

1*r^-1 = -1 // : 1

r^-1 = -1

-1 < 0

1/(r^1) = -1 // * r^1

1 = -1*r^1 // : -1

-1 = r^1

r = -1

t_1 = 1/4

r^-1-1/4 = 0

1*r^-1 = 1/4 // : 1

r^-1 = 1/4

-1 < 0

1/(r^1) = 1/4 // * r^1

1 = 1/4*r^1 // : 1/4

4 = r^1

r = 4

r in { -1, 4 }